-8b^2=11b

Solution for -8b^2=11b equation:

-8b^2=11b

We move all terms to the left:

-8b^2-(11b)=0

a = -8; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·(-8)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*-8}=\frac{0}{-16}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*-8}=\frac{22}{-16}
=-1+3/8
$